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Beliebt Word Problems >

Find two consecutive integers such that the square of the larger integer is ninteen more than nine times the smaller integer

Lösung

löse nach

tw o co n sec u t i v e in t e g ers s u c h t ha t t h e s q u a re o f t h e l a r g er in t e g er i s nin t ee n m ore t han nin e t im es t h e s ma ll er in t e g er

Lösung

The numbers : 9, 10 or - 2, - 1

Schritte zur Lösung

Represent the numbers with

x

:

First number : x

Consecutive number : x + 1

A.T.Q.:

(x + 1)^{2} = 19 + 9 x

Löse

(x + 1)^{2} = 19 + 9 x : x = 9, x = - 2

Setze ein

x = 9 : 10

Setze ein

x = - 2 : - 1

The numbers : 9, 10 or - 2, - 1

Beliebte Beispiele

The sum of two numbers is 45 . One number is 4 times as large as the other. What are the numbers?Two sevenths of a number is 30 less than the number. Find the number If 5 times a number is decreased by 12 , the result is 108 . What is the number?The sum of four times a number and 11 is 37. Find the number.For two consecutive integers, the sum of the smaller and twice the larger is 29. Find the smaller integer.