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Fractions Add, Subtract Unlike Denominators Calculator

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

θ

∞

∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

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Steps Examples

Generated by AI

eigenvektoren (

1	2	1
6	−1	0
−1	−2	−1

)

Solution

(

−1

−6

), (

−2

−3

), (

−1

)

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Solution steps

One step at a time

(

1	2	1
6	−1	0
−1	−2	−1

)

Matrix Eigenvektoren

Lass A eine Quadratmatrix, η ein Vektor und λ ein Skalar sein, welches diese Bedingung erfüllt: Aη=λη,
dann ist η ein Eigenvektor von A und λ ist ein Eigenwert, der damit verbunden ist.

Um die Eigenvektoren η zu finden, löse (A−λ I)η=0 für jeden Eigenwert λ

Ermittle die Eigenwerte von (

1	2	1
6	−1	0
−1	−2	−1

): λ=0, λ=3, λ=−4

Eigenvektoren für λ=0: (

−1

−6

)

Eigenvektoren für λ=3: (

−2

−3

)

Eigenvektoren für λ=−4: (

−1

)

Die Eigenvektoren für (

1	2	1
6	−1	0
−1	−2	−1

)

−1

−6

), (

−2

−3

), (

−1

)

Fractions Add, Subtract Unlike Denominators Examples

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Hallo, eine Frage stellen zu eigenvektoren (

1	2	1
6	−1	0
−1	−2	−1

) oder wählen Sie unten

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

Fractions Add, Subtract Unlike Denominators Calculator

Solution

Solution steps

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