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integral of (e^{1/x})/(x^2)

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eigenwerte (

1	2	3
4	5	6
7	8	9

)

Solution

λ=0, λ=15+3√332 , λ=15−3√332

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Solution steps

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(

1	2	3
4	5	6
7	8	9

)

Matrix Eigenwerte

Lass A eine Quadratmatrix sein, η einen Vektor und λ ein Skalar, das die Bedingung Aη=λη, erfüllt.
Dann ist λ der Eigenwert, der dem Eigenvektor λ von A zugordnet ist.

Die Eigenwerte von A sind die Wurzeln der charakteristischen Gleichung det(A−λ I)=0

det((

1	2	3
4	5	6
7	8	9

)−λ(

1	0	0
0	1	0
0	0	1

)): −λ³+15λ²+18λ

Löse −λ³+15λ²+18λ=0: λ=0, λ=15+3√332 , λ=15−3√332

Die Eigenwerte sind:

λ=0, λ=15+3√332 , λ=15−3√332

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1	2	3
4	5	6
7	8	9

) oder wählen Sie unten

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

integral of (e^{1/x})/(x^2)

Solution

Solution steps

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