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bereich 2log_{2}(2+x)-1

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

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implizite ableitung dydx , x=cos(5y )

Solution

dydx =y²5sin(5y )

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x=cos(5y )

Behandle y wie y(x)

Beide Seiten differenzieren: 1=5sin(5y )dydx y²

Isoliere dydx : dydx =y²5sin(5y )

dydx =y²5sin(5y )

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

bereich 2log_{2}(2+x)-1

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