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domain of and range f(x)=cos(2x+5)

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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x²+4x+3=0

Solution

x=−1, x=−3

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Das Quadrat vervollständigen

Quadratische Formel

Faktorisierungsmethode

One step at a time

x²+4x+3=0

Verschiebe 3 auf die rechte Seite

x²+4x=−3

Umschreiben in der Form (x+a)²=b

(x+2)²=1

Für f²(x)=a sind die Lösungen f(x)=√a, −√a

Löse x+2=√1: x=−1

Löse x+2=−√1: x=−3

Die Lösungen für die quadratische Gleichung sind:

x=−1, x=−3

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Hallo, eine Frage stellen zu x²+4x+3=0 oder wählen Sie aus den folgenden Optionen

Erklären Sie, wie quadratische Gleichungen gelöst werden

Lösen durch: Quadratische Formel

Lösen durch: Faktorisierungsmethode

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

domain of and range f(x)=cos(2x+5)

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