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domain of inverse f(x)=sin(x)

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

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reihenlösung 4x²y^{′ ′}−4x²y^′+(1−2x)y=0

Solution

y=c₁√x(1+x+x²2 +… +xⁿ(1)(2)… n +… )+c₂(ln(x)√x(1+x+x²2 +… +xⁿ(1)(2)… n +… )+√x(−x−3x²4 −11x³36 +… ))

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4x²y′ ′ −4x²y′ +(1−2x)y=0

Solve using series method: y=c₁√x(1+x+x²2 +… +xⁿ(1)(2)… n +… )+c₂(ln(x)√x(1+x+x²2 +… +xⁿ(1)(2)… n +… )+√x(−x−3x²4 −11x³36 +… ))

y=c₁√x(1+x+x²2 +… +xⁿ(1)(2)… n +… )+c₂(ln(x)√x(1+x+x²2 +… +xⁿ(1)(2)… n +… )+√x(−x−3x²4 −11x³36 +… ))

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

domain of inverse f(x)=sin(x)

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