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injective y=x^2

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

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improper fraction 2· 43

Solution

Decimal

2.66666…

Mixed Number

223

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Solution steps

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Definition Funktionsbereich

Die Menge der Werte der abhängigen Variablen, für die eine Funktion definiert ist

Schreibe um

x²+x+1x =y

Multipliziere beide Seiten mit x

x²+x+1=yx

Der Bereich ist die Menge an y, für die die Diskriminante größer oder gleich Null ist

Diskriminante x²+x+1=yx: y²−2y−3

y²−2y−3≥ 0 : y≤ −1 or y≥ 3

Prüfe, ob die Bereichsendpunkte innerhalb des Intervalls liegen

y=−1 : inbegriffen

y=3 : inbegriffen

Deshalb ist der Bereich:

f(x)≤ −1 or f(x)≥ 3

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

injective y=x^2

Solution

Solution steps

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