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points of on same line (1, 3), (2, 7), (3, 12)

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

θ

∞

∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

simplify solve for inverse tangent line

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projektion (2, 4), (−1, 5)

Solution

(

185

)

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Solution steps

One step at a time

proj_⃗ a(⃗ b )=⃗ b · ⃗ a |⃗ a |² · ⃗ a

⃗ a =(

), ⃗ b =(

−1

)

|⃗ a |: |(

)|=2√5

⃗ b · ⃗ a : (

−1

)(

)=18

⃗ b · ⃗ a |⃗ a |² · ⃗ a =18(2√5)² · (

)

Fasse zusammen: 18(2√5)² (

)=(

185

)

185

)

(

185

)

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Hallo, eine Frage stellen zu projektion (2,4),(−1,5) oder wählen Sie unten

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

points of on same line (1, 3), (2, 7), (3, 12)

Solution

Solution steps

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