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interzeption 1/(2x)

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

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log_□

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∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

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bereich 1x² +1x

Solution

−14 ≤ f(x)<0 or f(x)>0

Interval Notation

[−14 , 0)∪(0, ∞ )

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Definition Funktionsbereich

Die Menge der Werte der abhängigen Variablen, für die eine Funktion definiert ist

Der Funktionsbereich ergibt sich aus allen kombinierten Domänen der Kehrfunktionen.

Finde die Umkehrfunktionen von: 1x² +1x

Umkehrung von 1x² +1x : 1+√1+4x2x , 1−√1+4x2x

1+√1+4x2x , 1−√1+4x2x

Finde die Domäne für jede dieser Umkehrfunktionen

Bereich von 1+√1+4x2x : −14 ≤ x<0 or x>0

Bereich von 1−√1+4x2x : −14 ≤ x<0 or x>0

Kombiniere die Bereiche

−14 ≤ f(x)<0 or f(x)>0

Solve instead

domäne 1x² +1x

invers 1x² +1x

interzeption 1x² +1x

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

interzeption 1/(2x)

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