If a number is added to the numerator of 2/9 and the same number is subtracted from the denominator, the result is 10. Find the number.

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

θ

∞

∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

simplify solve for expand factor rationalize

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f(x)=2x+3, g(x)=−x²+5, (f(x)◦ g(x))(x)

Solution

−2x²+13

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Solution steps

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Finde (f ◦ g)(x) gegeben f(x)=2x+3, g(x)=−x²+5

f ◦ g=f(g(x))

g(x)=−x²+5

=f(−x²+5)

f(−x²+5): −2x²+13

=−2x²+13

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

If a number is added to the numerator of 2/9 and the same number is subtracted from the denominator, the result is 10. Find the number.

Solution

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