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taylor 4cos(x)
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Solution
4−2x2+16x4−1180x6+110080x8+…
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Solution steps
Solve by:
Find vertex using polynomial form
Find vertex using polynomial form
Find vertex using parabola form
Find vertex using vertex form
Find vertex using averaging the zeros
One step at a time
y=−3x2+5x
Parabola equation in polynomial form
The vertex of an up-down facing parabola of the form y=ax2+bx+cis xv=−b2a
The parabola parameters are:
a=−3,b=5,c=0
xv=−b2a
xv=−52(−3)
Vereinfache
xv=56
Plug in xv=56to find the yvvalue
yv=2512
Deshalb ist der Parabel Scheitelpunkt
(56,2512)
Wenn a<0,dann entspricht der Scheitpunkt dem Maximalwert Wenn a>0,dann entspricht der Scheitelpunkt dem Minimalwert a=−3